What is the answer to (3x-1)/2+(x-1)/3+x/5 =1 ?

The answer to (3x-1)/2+(x-1)/3+x/5 =1 is x= 55/61

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(3x-1)/2+(x-1)/3+x/5 =1

\frac{3 x - 1}{2} + \frac{x - 1}{3} + \frac{x}{5} = 1

x = \frac{55}{61}

Decimal Notation

x = 0.90163 \dots

Solution steps

\frac{3 x - 1}{2} + \frac{x - 1}{3} + \frac{x}{5} = 1

Multiply by LCM

15 (3 x - 1) + 10 (x - 1) + 6 x = 30

Expand

15 (3 x - 1) + 10 (x - 1) + 6 x : 61 x - 25

61 x - 25 = 30

Move

25

to the right side

61 x = 55

Divide both sides by

61

x = \frac{55}{61}

x, 5 (m - 4 x) = 25 m

5 x + 6 = - 4

\frac{h}{2} - (- 1) = 4

\frac{9}{5} (3 - x) = \frac{3}{4} (x - 3)

(1 + x)^{3} - (1 - x)^{3} = 2 x^{3}

What is the answer to (3x-1)/2+(x-1)/3+x/5 =1 ?
The answer to (3x-1)/2+(x-1)/3+x/5 =1 is x= 55/61
Solve for x: (3x-1)/2+(x-1)/3+x/5 =1
The solution is x= 55/61