What is the answer to -(2-3(x+4)-7x+3)=-4(4+x-(2x-3)-2) ?

The answer to -(2-3(x+4)-7x+3)=-4(4+x-(2x-3)-2) is x=-9/2

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-(2-3(x+4)-7x+3)=-4(4+x-(2x-3)-2)

- (2 - 3 (x + 4) - 7 x + 3) = - 4 (4 + x - (2 x - 3) - 2)

x = - \frac{9}{2}

Decimal Notation

x = - 4.5

Solution steps

- (2 - 3 (x + 4) - 7 x + 3) = - 4 (4 + x - (2 x - 3) - 2)

Expand

- (2 - 3 (x + 4) - 7 x + 3) : 10 x + 7

Expand

- 4 (4 + x - (2 x - 3) - 2) : 4 x - 20

10 x + 7 = 4 x - 20

Move

7

to the right side

10 x = 4 x - 27

Move

4 x

to the left side

6 x = - 27

Divide both sides by

6

x = - \frac{9}{2}

3 x - 20 = - 2 x

x, 27 x + 36 y + 28 = 0

7 x + 1 = 5 x - 7

x, - x = 2 - p

2^{11} + 2^{12} + 2^{13} + 2^{14} + 2^{15} = 62 x

What is the answer to -(2-3(x+4)-7x+3)=-4(4+x-(2x-3)-2) ?
The answer to -(2-3(x+4)-7x+3)=-4(4+x-(2x-3)-2) is x=-9/2
Solve for x: -(2-3(x+4)-7x+3)=-4(4+x-(2x-3)-2)
The solution is x=-9/2