What is the answer to (9(t-9)}{10}+1=t-\frac{3t-5)/2+23/5 ?

The answer to (9(t-9)}{10}+1=t-\frac{3t-5)/2+23/5 is t= 71/7

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(9(t-9)}{10}+1=t-\frac{3t-5)/2+23/5

\frac{9 ( t - 9 )}{10} + 1 = t - \frac{3 t - 5}{2} + \frac{23}{5}

t = \frac{71}{7}

Decimal Notation

t = 10.14285 \dots

Solution steps

\frac{9 ( t - 9 )}{10} + 1 = t - \frac{3 t - 5}{2} + \frac{23}{5}

Multiply by LCM

9 (t - 9) + 10 = 10 t - 5 (3 t - 5) + 46

Expand

9 (t - 9) + 10 : 9 t - 71

Expand

10 t - 5 (3 t - 5) + 46 : - 5 t + 71

9 t - 71 = - 5 t + 71

Move

71

to the right side

9 t = - 5 t + 142

Move

5 t

to the left side

14 t = 142

Divide both sides by

14

t = \frac{71}{7}

3 x - 10 = 2 x + 45

(x + \frac{1}{9}) (x + \frac{5}{3}) = (x + \frac{5}{3}) (x + 10)

y, y = \frac{6}{5} (1 - e^{- 20 t})

lo g_{2} (4 (90) + 6) + lo g_{2} (90) = 2

k, 13 t = \frac{9 k}{4} + 17

What is the answer to (9(t-9)}{10}+1=t-\frac{3t-5)/2+23/5 ?
The answer to (9(t-9)}{10}+1=t-\frac{3t-5)/2+23/5 is t= 71/7
Solve for t: (9(t-9)}{10}+1=t-\frac{3t-5)/2+23/5
The solution is t= 71/7