What are the solutions to the equation 49x^2-84x+36=0 ?

The solutions to the equation 49x^2-84x+36=0 are x= 6/7

Find the zeros of 49x^2-84x+36=0

The zeros of 49x^2-84x+36=0 are x= 6/7

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49 x^{2} - 84 x + 36 = 0

x = \frac{6}{7}

Decimal Notation

x = 0.85714 \dots

Solution steps

49 x^{2} - 84 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 84 ) \pm ( - 84 ) ^{2} - 4 \cdot 49 \cdot 36}{2 \cdot 49}

(- 84)^{2} - 4 \cdot 49 \cdot 36 = 0

x_{1, 2} = \frac{- ( - 84 ) \pm 0}{2 \cdot 49}

x = \frac{- ( - 84 )}{2 \cdot 49}

\frac{- ( - 84 )}{2 \cdot 49} = \frac{6}{7}

x = \frac{6}{7}

The solution to the quadratic equation is:

x = \frac{6}{7}

\frac{5 !}{2 ! \cdot ( 5 - 2 ) !}

3 x + 18 - x = 46

3 x + 12

- 5 < \frac{3 x - 1}{4} < 0

\frac{1 + \frac{1}{c - 1}}{1 - \frac{1}{c - 1}}

What are the solutions to the equation 49x^2-84x+36=0 ?
The solutions to the equation 49x^2-84x+36=0 are x= 6/7
Find the zeros of 49x^2-84x+36=0
The zeros of 49x^2-84x+36=0 are x= 6/7