What is the answer to (x-3)^2-(x-3)(x+3)=0 ?

The answer to (x-3)^2-(x-3)(x+3)=0 is x=3

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(x-3)^2-(x-3)(x+3)=0

(x - 3)^{2} - (x - 3) (x + 3) = 0

x = 3

Solution steps

(x - 3)^{2} - (x - 3) (x + 3) = 0

Expand

(x - 3)^{2} - (x - 3) (x + 3) : - 6 x + 18

- 6 x + 18 = 0

Move

18

to the right side

- 6 x = - 18

Divide both sides by

- 6

x = 3

\frac{y - 5}{3} = \frac{4}{5}

3 \cdot (x - 3) = 5 \cdot (x - 1) - 6 x

f (8) = 3 y

V = (3 h^{2} + 4)^{\frac{3}{2}} - 8

\frac{x - 3}{10} = \frac{x + 1}{15}

What is the answer to (x-3)^2-(x-3)(x+3)=0 ?
The answer to (x-3)^2-(x-3)(x+3)=0 is x=3
Solve for x: (x-3)^2-(x-3)(x+3)=0
The solution is x=3