What is the answer to solvefor x,P=y-x(y^2+2) ?

The answer to solvefor x,P=y-x(y^2+2) is x=-(P-y)/(y^2+2);\quad y\ne sqrt(2)i,y\ne-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,P=y-x(y^2+2)

solve for

x, P = y - x (y^{2} + 2)

x = - \frac{P - y}{y ^{2} + 2}; y \neq = 2 i, y \neq = - 2 i

Solution steps

P = y - x (y^{2} + 2)

Switch sides

y - x (y^{2} + 2) = P

Move

y

to the right side

- x (y^{2} + 2) = P - y

Divide both sides by

- (y^{2} + 2); y \neq = 2 i, y \neq = - 2 i

x = - \frac{P - y}{y ^{2} + 2}; y \neq = 2 i, y \neq = - 2 i

\frac{2 v - 3}{4} = \frac{6 v + 7}{3}

C - (- \frac{2}{3}) + 1 = \frac{1585}{927}

12 - 2 (x + 1) = 5

2 - \frac{x}{3} = \frac{- 5}{2}

x + 10 = 3 x - 2

What is the answer to solvefor x,P=y-x(y^2+2) ?
The answer to solvefor x,P=y-x(y^2+2) is x=-(P-y)/(y^2+2);\quad y\ne sqrt(2)i,y\ne-sqrt(2)i