What is the answer to (0+8-5)+k(0+2+1)=0 ?

The answer to (0+8-5)+k(0+2+1)=0 is k=-1

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(0+8-5)+k(0+2+1)=0

(0 + 8 - 5) + k (0 + 2 + 1) = 0

k = - 1

Solution steps

(0 + 8 - 5) + k (0 + 2 + 1) = 0

Remove parentheses:

(a) = a

0 + 8 - 5 + k (0 + 2 + 1) = 0

Add the numbers:

0 + 2 + 1 = 3

0 + 8 - 5 + 3 k = 0

Add/Subtract the numbers:

0 + 8 - 5 = 3

3 k + 3 = 0

Move

3

to the right side

3 k = - 3

Divide both sides by

3

k = - 1

\frac{2 x + 1}{5} - \frac{x + 1}{3} = 2 (\frac{3 x}{10} - (\frac{x}{6} - 1))

a, a + 2 b + 3 c = 1

x, a x + b y = cz

8 - 2 \cdot (3 x - 3) = x

- 0.1 x + \frac{7}{10} = \frac{2}{10}

What is the answer to (0+8-5)+k(0+2+1)=0 ?
The answer to (0+8-5)+k(0+2+1)=0 is k=-1
Solve for k: (0+8-5)+k(0+2+1)=0
The solution is k=-1