What are the solutions to the equation (x+3)^2-5=4 ?

The solutions to the equation (x+3)^2-5=4 are x=0,x=-6

Find the zeros of (x+3)^2-5=4

The zeros of (x+3)^2-5=4 are x=0,x=-6

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(x + 3)^{2} - 5 = 4

x = 0, x = - 6

Solution steps

(x + 3)^{2} - 5 = 4

Move

5

to the right side

(x + 3)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 9 : x = 0

Solve

x + 3 = - 9 : x = - 6

The solutions to the quadratic equation are:

x = 0, x = - 6

20 x^{2} + 12 x + 1 = 0

3 x + 36

\frac{9}{16} - \frac{1}{4}

(5 + 6 i)^{2}

3 \cdot 16

What are the solutions to the equation (x+3)^2-5=4 ?
The solutions to the equation (x+3)^2-5=4 are x=0,x=-6
Find the zeros of (x+3)^2-5=4
The zeros of (x+3)^2-5=4 are x=0,x=-6