What is the answer to solvefor x,2x+3y+4z=12 ?

The answer to solvefor x,2x+3y+4z=12 is x=(12-3y-4z)/2

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solvefor x,2x+3y+4z=12

solve for

x, 2 x + 3 y + 4 z = 12

x = \frac{12 - 3 y - 4 z}{2}

Solution steps

2 x + 3 y + 4 z = 12

Move

3 y

to the right side

2 x + 4 z = 12 - 3 y

Move

4 z

to the right side

2 x = 12 - 3 y - 4 z

Divide both sides by

2

x = \frac{12 - 3 y - 4 z}{2}

x, 3 x + 4 y = - 36

13 x - 2 (8 + 5 x) = 12 - 11 x

3 (x - 2) = 4 (- x + 3)

15 + 0.15 x = 0.2 x + 11

x, y + 2 x = 0

What is the answer to solvefor x,2x+3y+4z=12 ?
The answer to solvefor x,2x+3y+4z=12 is x=(12-3y-4z)/2