What is the answer to (125*2^{0+3})/(ln(2))+C=4000 ?

The answer to (125*2^{0+3})/(ln(2))+C=4000 is C=4000-(1000)/(ln(2))

Solve for C: (125*2^{0+3})/(ln(2))+C=4000

The solution is C=4000-(1000)/(ln(2))

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\frac{125 \cdot 2 ^{0 + 3}}{ln ( 2 )} + C = 4000

C = 4000 - \frac{1000}{ln ( 2 )}

Decimal Notation

C = 2557.30495 \dots

Solution steps

\frac{125 \cdot 2 ^{0 + 3}}{ln ( 2 )} + C = 4000

Add the numbers:

0 + 3 = 3

\frac{2 ^{3} \cdot 125}{ln ( 2 )} + C = 4000

125 \cdot 2^{3} = 1000

\frac{1000}{ln ( 2 )} + C = 4000

Move

\frac{1000}{ln ( 2 )}

to the right side

C = 4000 - \frac{1000}{ln ( 2 )}

\frac{5}{2} (\frac{7 + x}{3}) = \frac{1}{3} (5 - \frac{5 x}{2}) + \frac{3 x}{2}

\frac{1}{3} (z - 2) + \frac{4}{3} z = 2 z + \frac{4}{3}

4 (3 t - 2) = 88

4 (t - 5) + 3 = t + 1

(x + 3)^{2} - 4 = (x - 2) (x + 8) + 21

What is the answer to (125*2^{0+3})/(ln(2))+C=4000 ?
The answer to (125*2^{0+3})/(ln(2))+C=4000 is C=4000-(1000)/(ln(2))
Solve for C: (125*2^{0+3})/(ln(2))+C=4000
The solution is C=4000-(1000)/(ln(2))