What are the solutions to the equation -4x+4=-x^2 ?

The solutions to the equation -4x+4=-x^2 are x=2

Find the zeros of -4x+4=-x^2

The zeros of -4x+4=-x^2 are x=2

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- 4 x + 4 = - x^{2}

x = 2

Solution steps

- 4 x + 4 = - x^{2}

Switch sides

- x^{2} = - 4 x + 4

Move

4

to the left side

- x^{2} - 4 = - 4 x

Move

4 x

to the left side

- x^{2} - 4 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

4^{2} - 4 (- 1) (- 4) = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 ( - 1 )}

x = \frac{- 4}{2 ( - 1 )}

\frac{- 4}{2 ( - 1 )} = 2

x = 2

The solution to the quadratic equation is:

x = 2

x^{2} - 16 x + 28

(x - 2)^{2} - 16

\frac{4 x - 6}{12} - \frac{3 x - 8}{4} = \frac{2 x - 9}{6} - \frac{x - 4}{8}

58 = 837 x

2 x + 2 = 12

What are the solutions to the equation -4x+4=-x^2 ?
The solutions to the equation -4x+4=-x^2 are x=2
Find the zeros of -4x+4=-x^2
The zeros of -4x+4=-x^2 are x=2