What is the answer to solvefor x,2x+3y= 1/z ?

The answer to solvefor x,2x+3y= 1/z is x=(1-3yz)/(2z)

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solvefor x,2x+3y= 1/z

solve for

x, 2 x + 3 y = \frac{1}{z}

x = \frac{1 - 3 yz}{2 z}

Solution steps

2 x + 3 y = \frac{1}{z}

Move

3 y

to the right side

2 x = \frac{1}{z} - 3 y

Divide both sides by

2

x = \frac{1 - 3 yz}{2 z}

0.927 = 1 - (1 - x) \cdot \frac{14}{11}

\frac{2 x}{6.4} - 5.7 = 2.15

b, 3.95 m + 8.95 b = 47.65

2 (3 x - 4) = - 5 (2 x - 7)

I = \frac{n \cdot 1 0 ^{- 3}}{4 \cdot π \cdot ( n ^{2} )} \cdot 1 0^{9}

What is the answer to solvefor x,2x+3y= 1/z ?
The answer to solvefor x,2x+3y= 1/z is x=(1-3yz)/(2z)