What is the answer to x^2-4x+3=x^2+2x+3 ?

The answer to x^2-4x+3=x^2+2x+3 is x=0

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x^2-4x+3=x^2+2x+3

x^{2} - 4 x + 3 = x^{2} + 2 x + 3

x = 0

Solution steps

x^{2} - 4 x + 3 = x^{2} + 2 x + 3

Subtract

x^{2} + 3

from both sides

x^{2} - 4 x + 3 - (x^{2} + 3) = x^{2} + 2 x + 3 - (x^{2} + 3)

Simplify

- 4 x = 2 x

Move

2 x

to the left side

- 6 x = 0

Divide both sides by

- 6

x = 0

\frac{2}{5} h + 5 = \frac{3}{5} h + 2

\frac{π}{2} (x - 3) = \frac{π}{2}

w + \frac{1}{2} = \frac{1}{4} w + 2

x, x y^{2} + x y - 6 x - 3 = 0

t, i = p r t

What is the answer to x^2-4x+3=x^2+2x+3 ?
The answer to x^2-4x+3=x^2+2x+3 is x=0
Solve for x: x^2-4x+3=x^2+2x+3
The solution is x=0