What is the answer to 7/4 (4x-4/7)+8x=-1 ?

The answer to 7/4 (4x-4/7)+8x=-1 is x=0

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7/4 (4x-4/7)+8x=-1

\frac{7}{4} (4 x - \frac{4}{7}) + 8 x = - 1

x = 0

Solution steps

\frac{7}{4} (4 x - \frac{4}{7}) + 8 x = - 1

Multiply

\frac{7}{4} (4 x - \frac{4}{7}) : \frac{7 ( 4 x - \frac{4}{7} )}{4}

\frac{7 ( 4 x - \frac{4}{7} )}{4} + 8 x = - 1

Multiply both sides by

4

7 (4 x - \frac{4}{7}) + 32 x = - 4

Expand

7 (4 x - \frac{4}{7}) + 32 x : 60 x - 4

60 x - 4 = - 4

Move

4

to the right side

60 x = 0

Divide both sides by

60

x = 0

\frac{7 x + 2}{2} - \frac{9 x - 8}{4} = 8

m, h = m + (- 2 2)

10 (x - 1) = 8 x - 2

x, x + 3 y + 10 = 0

72 - x = 20 \cdot 3

What is the answer to 7/4 (4x-4/7)+8x=-1 ?
The answer to 7/4 (4x-4/7)+8x=-1 is x=0
Solve for x: 7/4 (4x-4/7)+8x=-1
The solution is x=0