What is the answer to solvefor x,2y=1+xy^3 ?

The answer to solvefor x,2y=1+xy^3 is x=(2y-1)/(y^3);\quad y\ne 0

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solvefor x,2y=1+xy^3

solve for

x, 2 y = 1 + x y^{3}

x = \frac{2 y - 1}{y ^{3}}; y \neq = 0

Solution steps

2 y = 1 + x y^{3}

Switch sides

1 + x y^{3} = 2 y

Move

1

to the right side

x y^{3} = 2 y - 1

Divide both sides by

y^{3}; y \neq = 0

x = \frac{2 y - 1}{y ^{3}}; y \neq = 0

\frac{1}{2} (x - \frac{7}{3}) - \frac{1}{3} (x - \frac{7}{4}) + \frac{1}{4} (x - \frac{7}{5}) = 0

3 x = 10 x + 21

x, k x + 7 = 4

(x + 2) + (x - 3) + (x - 7) + (x + 4) = 360

(x - 3) + (4 x - 6) + (2 x + 3) + (3 x - 4) = 360

What is the answer to solvefor x,2y=1+xy^3 ?
The answer to solvefor x,2y=1+xy^3 is x=(2y-1)/(y^3);\quad y\ne 0