What is the answer to log_{10}(3)(2-x)=-2 ?

The answer to log_{10}(3)(2-x)=-2 is x=(2+2log_{10}(3))/(log_{10)(3)}

Solve for x: log_{10}(3)(2-x)=-2

The solution is x=(2+2log_{10}(3))/(log_{10)(3)}

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lo g_{10} (3) (2 - x) = - 2

x = \frac{2 + 2 lo g _{10} ( 3 )}{lo g _{10} ( 3 )}

Decimal Notation

x = 6.19180 \dots

Solution steps

lo g_{10} (3) (2 - x) = - 2

Divide both sides by

lo g_{10} (3)

2 - x = - \frac{2}{lo g _{10} ( 3 )}

Move

2

to the right side

- x = - \frac{2}{lo g _{10} ( 3 )} - 2

Divide both sides by

- 1

x = \frac{2 + 2 lo g _{10} ( 3 )}{lo g _{10} ( 3 )}

4 + 5 x = 44

5 (x + 2) - 13 = 2 (3 x - 1)

\frac{x}{4} - \frac{x}{6} = 3

f (m) = (8 m^{5} - 4 m)^{4}

3 (22 - (\frac{X}{2})) = 18

What is the answer to log_{10}(3)(2-x)=-2 ?
The answer to log_{10}(3)(2-x)=-2 is x=(2+2log_{10}(3))/(log_{10)(3)}
Solve for x: log_{10}(3)(2-x)=-2
The solution is x=(2+2log_{10}(3))/(log_{10)(3)}