What are the solutions to the equation 9x^2-42x+49=0 ?

The solutions to the equation 9x^2-42x+49=0 are x= 7/3

Find the zeros of 9x^2-42x+49=0

The zeros of 9x^2-42x+49=0 are x= 7/3

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9 x^{2} - 42 x + 49 = 0

x = \frac{7}{3}

Decimal Notation

x = 2.33333 \dots

Solution steps

9 x^{2} - 42 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 42 ) \pm ( - 42 ) ^{2} - 4 \cdot 9 \cdot 49}{2 \cdot 9}

(- 42)^{2} - 4 \cdot 9 \cdot 49 = 0

x_{1, 2} = \frac{- ( - 42 ) \pm 0}{2 \cdot 9}

x = \frac{- ( - 42 )}{2 \cdot 9}

\frac{- ( - 42 )}{2 \cdot 9} = \frac{7}{3}

x = \frac{7}{3}

The solution to the quadratic equation is:

x = \frac{7}{3}

3 x + 2 = x - 7

(\frac{6}{7})^{0}

x + \frac{x}{3} \leq 20

4 x^{2} = 13 x + 35

\frac{( - 2 ) ^{5}}{( - 3 ) ^{3}}

What are the solutions to the equation 9x^2-42x+49=0 ?
The solutions to the equation 9x^2-42x+49=0 are x= 7/3
Find the zeros of 9x^2-42x+49=0
The zeros of 9x^2-42x+49=0 are x= 7/3