What is the answer to solvefor x,y=f^{-1}(x) ?

The answer to solvefor x,y=f^{-1}(x) is x=yf;\quad f\ne 0

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solvefor x,y=f^{-1}(x)

solve for

x, y = f^{- 1} (x)

x = y f; f \neq = 0

Solution steps

y = f^{- 1} (x)

Switch sides

f^{- 1} x = y

Simplify

f^{- 1} : \frac{1}{f}

\frac{1}{f} x = y

Multiply both sides by

f

x = y f; f \neq = 0

44 + 56 + 17 x - 5 = 180

x - \frac{1}{a} = \frac{x}{a}

\frac{3 y + 4}{2} + \frac{2 y - 5}{3} = \frac{31}{2}

\frac{3}{4} (\frac{1}{4} x + 8) - (\frac{1}{2} x + 2) = \frac{3}{8} (4 - x) - \frac{1}{4} x

\frac{x + 1}{2} + 3 x = \frac{5}{4}

What is the answer to solvefor x,y=f^{-1}(x) ?
The answer to solvefor x,y=f^{-1}(x) is x=yf;\quad f\ne 0