What is the answer to x^2+81=x^2+20x+100 ?

The answer to x^2+81=x^2+20x+100 is x=-19/20

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x^2+81=x^2+20x+100

x^{2} + 81 = x^{2} + 20 x + 100

x = - \frac{19}{20}

Decimal Notation

x = - 0.95

Solution steps

x^{2} + 81 = x^{2} + 20 x + 100

Subtract

x^{2}

from both sides

x^{2} + 81 - x^{2} = x^{2} + 20 x + 100 - x^{2}

Simplify

81 = 20 x + 100

Switch sides

20 x + 100 = 81

Move

100

to the right side

20 x = - 19

Divide both sides by

20

x = - \frac{19}{20}

\frac{2}{5} w = 15

\frac{1}{6} X + 2 X - 1 = \frac{1}{3} (X + 9)

x, y = f - 5

x, y = f + 8

\frac{x}{3} - \frac{3 x + 2}{6} - 1 = \frac{4 x}{2}

What is the answer to x^2+81=x^2+20x+100 ?
The answer to x^2+81=x^2+20x+100 is x=-19/20
Solve for x: x^2+81=x^2+20x+100
The solution is x=-19/20