What is the answer to x^4-16=(x^2+4)(x^2-4) ?

The answer to x^4-16=(x^2+4)(x^2-4) is True for all x

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x^4-16=(x^2+4)(x^2-4)

x^{4} - 16 = (x^{2} + 4) (x^{2} - 4)

True for all x

Solution steps

x^{4} - 16 = (x^{2} + 4) (x^{2} - 4)

Expand

(x^{2} + 4) (x^{2} - 4) : x^{4} - 16

x^{4} - 16 = x^{4} - 16

Move

16

to the right side

x^{4} = x^{4}

Move

x^{4}

to the left side

0 = 0

Both sides are equal

True for all x

x, g = f - 3

7 (x + 4) - 6 (x + 3) = x + 5

\frac{1}{5} (3 - 7 x) + \frac{8}{4} - (- 3 x + 5) = 3 x - \frac{x}{4} + 12

\frac{5 w + 7}{2} - \frac{w + 4}{5} = 1 - \frac{3 - w}{4}

- 4 x - 8 = - 8 x + 16

What is the answer to x^4-16=(x^2+4)(x^2-4) ?
The answer to x^4-16=(x^2+4)(x^2-4) is True for all x
Solve for x: x^4-16=(x^2+4)(x^2-4)
The solution is True for all x