What is the answer to 3x-(-2x+3)=3x-(x+2) ?

The answer to 3x-(-2x+3)=3x-(x+2) is x= 1/3

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3x-(-2x+3)=3x-(x+2)

3 x - (- 2 x + 3) = 3 x - (x + 2)

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

3 x - (- 2 x + 3) = 3 x - (x + 2)

Subtract

3 x

from both sides

3 x - (- 2 x + 3) - 3 x = 3 x - (x + 2) - 3 x

Simplify

- (- 2 x + 3) = - (x + 2)

Expand

- (- 2 x + 3) : 2 x - 3

Expand

- (x + 2) : - x - 2

2 x - 3 = - x - 2

Move

3

to the right side

2 x = - x + 1

Move

x

to the left side

3 x = 1

Divide both sides by

3

x = \frac{1}{3}

2 y + (\frac{- 5}{4}) = 75

- 6 = - (x - 5) - 3 (5 + 2 x) - 4 (2 x - 4)

x, y = \frac{1}{3} f

x, 4 x - 2 y = - 5

3 (4 x - 7) = 10 (x + 5)

What is the answer to 3x-(-2x+3)=3x-(x+2) ?
The answer to 3x-(-2x+3)=3x-(x+2) is x= 1/3
Solve for x: 3x-(-2x+3)=3x-(x+2)
The solution is x= 1/3