What is the answer to (x-1)^2-1=(2x-1)(2x+1)-3x^2 ?

The answer to (x-1)^2-1=(2x-1)(2x+1)-3x^2 is x= 1/2

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(x-1)^2-1=(2x-1)(2x+1)-3x^2

(x - 1)^{2} - 1 = (2 x - 1) (2 x + 1) - 3 x^{2}

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

(x - 1)^{2} - 1 = (2 x - 1) (2 x + 1) - 3 x^{2}

Expand

(x - 1)^{2} - 1 : x^{2} - 2 x

Expand

(2 x - 1) (2 x + 1) - 3 x^{2} : x^{2} - 1

x^{2} - 2 x = x^{2} - 1

Move

x^{2}

to the left side

- 2 x = - 1

Divide both sides by

- 2

x = \frac{1}{2}

(x + b) = a + x

6 (3 k + 5) = 39

\frac{x + 8 - 7}{3 - 4} + 2 = 3

5 - 6 x = - x

5 = 2 x + 3

What is the answer to (x-1)^2-1=(2x-1)(2x+1)-3x^2 ?
The answer to (x-1)^2-1=(2x-1)(2x+1)-3x^2 is x= 1/2
Solve for x: (x-1)^2-1=(2x-1)(2x+1)-3x^2
The solution is x= 1/2