What is the answer to 2z-2=3(z-1)-5(6-2z) ?

The answer to 2z-2=3(z-1)-5(6-2z) is z= 31/11

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2z-2=3(z-1)-5(6-2z)

2 z - 2 = 3 (z - 1) - 5 (6 - 2 z)

z = \frac{31}{11}

Decimal Notation

z = 2.81818 \dots

Solution steps

2 z - 2 = 3 (z - 1) - 5 (6 - 2 z)

Expand

3 (z - 1) - 5 (6 - 2 z) : 13 z - 33

2 z - 2 = 13 z - 33

Move

2

to the right side

2 z = 13 z - 31

Move

13 z

to the left side

- 11 z = - 31

Divide both sides by

- 11

z = \frac{31}{11}

a x - b x = a + b

x, \frac{x}{r} - s = t

- 3 h + (- 13.84) = 3.56

(4 x - 3)^{2} - 16 x^{2} = 9 - 24 x

\frac{3 x}{5 - 4} = - 6 + x

What is the answer to 2z-2=3(z-1)-5(6-2z) ?
The answer to 2z-2=3(z-1)-5(6-2z) is z= 31/11
Solve for z: 2z-2=3(z-1)-5(6-2z)
The solution is z= 31/11