What is the answer to log_{10}(2)(x+3)+log_{10}(2)(x-3)=4 ?

The answer to log_{10}(2)(x+3)+log_{10}(2)(x-3)=4 is x= 2/(log_{10)(2)}

Solve for x: log_{10}(2)(x+3)+log_{10}(2)(x-3)=4

The solution is x= 2/(log_{10)(2)}

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lo g_{10} (2) (x + 3) + lo g_{10} (2) (x - 3) = 4

x = \frac{2}{lo g _{10} ( 2 )}

Decimal Notation

x = 6.64385 \dots

Solution steps

lo g_{10} (2) (x + 3) + lo g_{10} (2) (x - 3) = 4

Expand

lo g_{10} (2) (x + 3) + lo g_{10} (2) (x - 3) : 2 lo g_{10} (2) x

2 lo g_{10} (2) x = 4

Divide both sides by

2 lo g_{10} (2)

x = \frac{2}{lo g _{10} ( 2 )}

119 + y + 1 1^{2} \cdot = 2^{4} \cdot 1 0^{1} + 3^{4}

- 4 + x = - 9

z = - 2 + 2 3 i

3 x - 17 = x + 13

- 3 x - 4 + 4 x - 40 x = 300 - 3 + 40

What is the answer to log_{10}(2)(x+3)+log_{10}(2)(x-3)=4 ?
The answer to log_{10}(2)(x+3)+log_{10}(2)(x-3)=4 is x= 2/(log_{10)(2)}
Solve for x: log_{10}(2)(x+3)+log_{10}(2)(x-3)=4
The solution is x= 2/(log_{10)(2)}