What is the answer to log_{10}(3)(2-x)=1 ?

The answer to log_{10}(3)(2-x)=1 is x=-(1-2log_{10}(3))/(log_{10)(3)}

Solve for x: log_{10}(3)(2-x)=1

The solution is x=-(1-2log_{10}(3))/(log_{10)(3)}

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lo g_{10} (3) (2 - x) = 1

x = - \frac{1 - 2 lo g _{10} ( 3 )}{lo g _{10} ( 3 )}

Decimal

x = - 0.09590 \dots

Solution steps

lo g_{10} (3) (2 - x) = 1

Divide both sides by

lo g_{10} (3)

2 - x = \frac{1}{lo g _{10} ( 3 )}

Move

2

to the right side

- x = \frac{1}{lo g _{10} ( 3 )} - 2

Divide both sides by

- 1

x = - \frac{1 - 2 lo g _{10} ( 3 )}{lo g _{10} ( 3 )}

\frac{3 ( x - 1 )}{4} - \frac{2 ( x - 2 )}{3} = \frac{x - 2}{2}

- x = - 5

x, 12 x + 5 y + 26 = 0

10000 (x - 0.85) = 0

b, A = \frac{1}{2} (b + b) h

What is the answer to log_{10}(3)(2-x)=1 ?
The answer to log_{10}(3)(2-x)=1 is x=-(1-2log_{10}(3))/(log_{10)(3)}
Solve for x: log_{10}(3)(2-x)=1
The solution is x=-(1-2log_{10}(3))/(log_{10)(3)}