What is the answer to solvefor k,f=klog_{10}(t+10) ?

The answer to solvefor k,f=klog_{10}(t+10) is k= f/(log_{10)(t+10)};\quad t\ne-9

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solvefor k,f=klog_{10}(t+10)

solve for

k, f = k lo g_{10} (t + 10)

k = \frac{f}{lo g _{10} ( t + 10 )}; t \neq = - 9

Solution steps

f = k lo g_{10} (t + 10)

Switch sides

k lo g_{10} (t + 10) = f

Divide both sides by

lo g_{10} (t + 10); t \neq = - 9

k = \frac{f}{lo g _{10} ( t + 10 )}; t \neq = - 9

\frac{x}{2} = \frac{3 x}{2} - x + 1

\frac{5 x}{6} = \frac{8}{3}

4 (x - 2) - \frac{5}{2} (x + 3) = \frac{1}{4}

3 (x + 2) + 4 (2 x + 1) = 11 x - 2 (x + 6)

x, f^{- 1} (x) = 59 x - 1

What is the answer to solvefor k,f=klog_{10}(t+10) ?
The answer to solvefor k,f=klog_{10}(t+10) is k= f/(log_{10)(t+10)};\quad t\ne-9