What is the answer to x/(3-a)-(3-a)/(3+a)=(6a-12)/(9+3a-6-2a) ?

The answer to x/(3-a)-(3-a)/(3+a)=(6a-12)/(9+3a-6-2a) is x=((5a-9)(3-a))/(a+3);\quad a\ne 3

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x/(3-a)-(3-a)/(3+a)=(6a-12)/(9+3a-6-2a)

\frac{x}{3 - a} - \frac{3 - a}{3 + a} = \frac{6 a - 12}{9 + 3 a - 6 - 2 a}

x = \frac{( 5 a - 9 ) ( 3 - a )}{a + 3}; a \neq = 3

Solution steps

\frac{x}{3 - a} - \frac{3 - a}{3 + a} = \frac{6 a - 12}{9 + 3 a - 6 - 2 a}

9 + 3 a - 6 - 2 a = a + 3

\frac{x}{3 - a} - \frac{3 - a}{3 + a} = \frac{6 a - 12}{a + 3}

Move

\frac{3 - a}{3 + a}

to the right side

\frac{x}{3 - a} = \frac{5 a - 9}{a + 3}

Multiply both sides by

3 - a

x = \frac{( 5 a - 9 ) ( 3 - a )}{a + 3}; a \neq = 3

(x + 6)^{2} = x^{2}

x, 2 x + y - z = 3

(2 p - 1) - (3 p + 2) = 1

6 x + 7 = 3 x + 19

12 (5 w + 2) = 1164

What is the answer to x/(3-a)-(3-a)/(3+a)=(6a-12)/(9+3a-6-2a) ?
The answer to x/(3-a)-(3-a)/(3+a)=(6a-12)/(9+3a-6-2a) is x=((5a-9)(3-a))/(a+3);\quad a\ne 3