What are the solutions to the equation c^2-6c+2=0 ?

The solutions to the equation c^2-6c+2=0 are c=3+sqrt(7),c=3-sqrt(7)

Find the zeros of c^2-6c+2=0

The zeros of c^2-6c+2=0 are c=3+sqrt(7),c=3-sqrt(7)

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c^{2} - 6 c + 2 = 0

c = 3 + 7, c = 3 - 7

Decimal Notation

c = 5.64575 \dots, c = 0.35424 \dots

Solution steps

c^{2} - 6 c + 2 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 2 = 27

c_{1, 2} = \frac{- ( - 6 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 6 ) + 2 7}{2 \cdot 1}, c_{2} = \frac{- ( - 6 ) - 2 7}{2 \cdot 1}

c = \frac{- ( - 6 ) + 2 7}{2 \cdot 1} : 3 + 7

c = \frac{- ( - 6 ) - 2 7}{2 \cdot 1} : 3 - 7

The solutions to the quadratic equation are:

c = 3 + 7, c = 3 - 7

64 x^{2} - 225 y^{2}

\frac{- 1 + ( - 1 ) ^{1} + 2 π ( - 1 ) ^{1}}{π ( 1 ) ^{2}}

5 u^{2} + 22 u + 8

- 7 x - 6 > 15

\frac{2}{5} (4)

What are the solutions to the equation c^2-6c+2=0 ?
The solutions to the equation c^2-6c+2=0 are c=3+sqrt(7),c=3-sqrt(7)
Find the zeros of c^2-6c+2=0
The zeros of c^2-6c+2=0 are c=3+sqrt(7),c=3-sqrt(7)