What is the answer to solvefor x,2(x-y)^2+4xy-2x^2+8-y^2=10 ?

The answer to solvefor x,2(x-y)^2+4xy-2x^2+8-y^2=10 is True for all x;\quad 2y^2=y^2+2

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solvefor x,2(x-y)^2+4xy-2x^2+8-y^2=10

solve for

x, 2 (x - y)^{2} + 4 x y - 2 x^{2} + 8 - y^{2} = 10

True for all x; 2 y^{2} = y^{2} + 2

Solution steps

2 (x - y)^{2} + 4 x y - 2 x^{2} + 8 - y^{2} = 10

Move

y^{2}

to the right side

2 (x - y)^{2} + 4 x y - 2 x^{2} + 8 = 10 + y^{2}

Move

8

to the right side

2 (x - y)^{2} + 4 x y - 2 x^{2} = y^{2} + 2

Expand

2 (x - y)^{2} + 4 x y - 2 x^{2} : 2 y^{2}

2 y^{2} = y^{2} + 2

Both sides are equal

True for all x; 2 y^{2} = y^{2} + 2

\frac{8 x + 2}{6} + 8 x = 1

x, 6 x + 4 y = 16

x, 3 x + 2 y = 35

3 (6 - 1) - 2 \cdot x = 1

\frac{1 - 2 x}{3} = \frac{x + 1}{2}

What is the answer to solvefor x,2(x-y)^2+4xy-2x^2+8-y^2=10 ?
The answer to solvefor x,2(x-y)^2+4xy-2x^2+8-y^2=10 is True for all x;\quad 2y^2=y^2+2