What is the answer to log_{10}(2)(9x)-4log_{10}(2)(4)=1 ?

The answer to log_{10}(2)(9x)-4log_{10}(2)(4)=1 is x=(1+16log_{10}(2))/(9log_{10)(2)}

Solve for x: log_{10}(2)(9x)-4log_{10}(2)(4)=1

The solution is x=(1+16log_{10}(2))/(9log_{10)(2)}

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lo g_{10} (2) (9 x) - 4 lo g_{10} (2) (4) = 1

x = \frac{1 + 16 lo g _{10} ( 2 )}{9 lo g _{10} ( 2 )}

Decimal Notation

x = 2.14688 \dots

Solution steps

lo g_{10} (2) (9 x) - 4 lo g_{10} (2) (4) = 1

Remove parentheses:

(a) = a

9 lo g_{10} (2) x - 4 \cdot 4 lo g_{10} (2) = 1

Multiply the numbers:

4 \cdot 4 = 16

9 lo g_{10} (2) x - 16 lo g_{10} (2) = 1

Move

16 lo g_{10} (2)

to the right side

9 lo g_{10} (2) x = 1 + 16 lo g_{10} (2)

Divide both sides by

9 lo g_{10} (2)

x = \frac{1 + 16 lo g _{10} ( 2 )}{9 lo g _{10} ( 2 )}

x, 3 (x - 1) + 2 y + 1 = 0

\frac{3 x}{4} + \frac{1}{2} = \frac{2 x - 3}{4}

\frac{4 x + 1}{2} = \frac{x - 5}{2}

\frac{2 x}{5} + \frac{3}{4} = \frac{1}{3} + \frac{x}{2}

x, g = - 2 f

What is the answer to log_{10}(2)(9x)-4log_{10}(2)(4)=1 ?
The answer to log_{10}(2)(9x)-4log_{10}(2)(4)=1 is x=(1+16log_{10}(2))/(9log_{10)(2)}
Solve for x: log_{10}(2)(9x)-4log_{10}(2)(4)=1
The solution is x=(1+16log_{10}(2))/(9log_{10)(2)}