What is the answer to solvefor n,θ=(3pi)/2+2pin ?

The answer to solvefor n,θ=(3pi)/2+2pin is n=(2θ-3pi)/(4pi)

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solvefor n,θ=(3pi)/2+2pin

solve for

n, θ = \frac{3 π}{2} + 2 πn

n = \frac{2 θ - 3 π}{4 π}

Solution steps

θ = \frac{3 π}{2} + 2 πn

Switch sides

\frac{3 π}{2} + 2 πn = θ

Move

\frac{3 π}{2}

to the right side

2 πn = θ - \frac{3 π}{2}

Divide both sides by

2 π

n = \frac{2 θ - 3 π}{4 π}

11 x + 10 = 6 x - 30

2 x + 3 (x - 1) = 6 (x - 3) + 13

4 x + 2 (x - 1) + 4 = - 4 x

x, - 8 x + 2 y = 6

2 (6 x - 4) - 5 (4 x - 6) = 22 - 3 (3 x - 2)

What is the answer to solvefor n,θ=(3pi)/2+2pin ?
The answer to solvefor n,θ=(3pi)/2+2pin is n=(2θ-3pi)/(4pi)