What is the answer to solvefor a,b^2-4ac=16 ?

The answer to solvefor a,b^2-4ac=16 is a=-(16-b^2)/(4c);\quad c\ne 0

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solvefor a,b^2-4ac=16

solve for

a, b^{2} - 4 a c = 16

a = - \frac{16 - b ^{2}}{4 c}; c \neq = 0

Solution steps

b^{2} - 4 a c = 16

Move

b^{2}

to the right side

- 4 a c = 16 - b^{2}

Divide both sides by

- 4 c; c \neq = 0

a = - \frac{16 - b ^{2}}{4 c}; c \neq = 0

32 = x - 13

\frac{2 x}{3} - 1 = \frac{x - 2}{2}

x, 9 = 5 x + 3 y

37 - 8 x = - 7 (x - 6)

3 (y - 6) = 0

What is the answer to solvefor a,b^2-4ac=16 ?
The answer to solvefor a,b^2-4ac=16 is a=-(16-b^2)/(4c);\quad c\ne 0