What is the answer to (3x-3)/3+(4x+1)/2 =0 ?

The answer to (3x-3)/3+(4x+1)/2 =0 is x= 1/6

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(3x-3)/3+(4x+1)/2 =0

\frac{3 x - 3}{3} + \frac{4 x + 1}{2} = 0

x = \frac{1}{6}

Decimal Notation

x = 0.16666 \dots

Solution steps

\frac{3 x - 3}{3} + \frac{4 x + 1}{2} = 0

Multiply by LCM

6 (x - 1) + 3 (4 x + 1) = 0

Expand

6 (x - 1) + 3 (4 x + 1) : 18 x - 3

18 x - 3 = 0

Move

3

to the right side

18 x = 3

Divide both sides by

18

x = \frac{1}{6}

\frac{3}{5} y + 3 = 11 + \frac{1}{5} y

12 - x = 7 x + 32

x, p = 3 x + 3 y + 3

a, 3 a + 4 b = a - 8 b + 24

\frac{1}{3} x + \frac{1}{2} x - 2 = \frac{1}{2} x - 7

What is the answer to (3x-3)/3+(4x+1)/2 =0 ?
The answer to (3x-3)/3+(4x+1)/2 =0 is x= 1/6
Solve for x: (3x-3)/3+(4x+1)/2 =0
The solution is x= 1/6