What is the answer to 64-((3y+8y+y))/(40)=37 ?

The answer to 64-((3y+8y+y))/(40)=37 is y=90

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64-((3y+8y+y))/(40)=37

64 - \frac{( 3 y + 8 y + y )}{40} = 37

y = 90

Solution steps

64 - \frac{( 3 y + 8 y + y )}{40} = 37

\frac{3 y + 8 y + y}{40} = \frac{3 y}{10}

64 - \frac{3 y}{10} = 37

Move

64

to the right side

- \frac{3 y}{10} = - 27

Multiply both sides by

10

- 3 y = - 270

Divide both sides by

- 3

y = 90

a (n) = (\frac{1}{2})^{n}

\frac{1}{5} f - \frac{2}{3} = - \frac{1}{5} f + \frac{2}{3}

12 x - 4 x + 2 = 10

22 = 8

4 y + 6 = - 2 y + 30

What is the answer to 64-((3y+8y+y))/(40)=37 ?
The answer to 64-((3y+8y+y))/(40)=37 is y=90
Solve for y: 64-((3y+8y+y))/(40)=37
The solution is y=90