What is the answer to (x+2a)/a+(x+3b)/b =2 ?

The answer to (x+2a)/a+(x+3b)/b =2 is x=-(3ab)/(a+b);\quad ab\ne 0,a\ne-b

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(x+2a)/a+(x+3b)/b =2

\frac{x + 2 a}{a} + \frac{x + 3 b}{b} = 2

x = - \frac{3 ab}{a + b}; ab \neq = 0, a \neq = - b

Solution steps

\frac{x + 2 a}{a} + \frac{x + 3 b}{b} = 2

Multiply by LCM

b (x + 2 a) + a (x + 3 b) = 2 ab; ab \neq = 0

Expand

b (x + 2 a) + a (x + 3 b) : a x + b x + 5 ab

a x + b x + 5 ab = 2 ab; ab \neq = 0

Move

5 ab

to the right side

a x + b x = - 3 ab; ab \neq = 0

Factor

a x + b x : x (a + b)

x (a + b) = - 3 ab; ab \neq = 0

Divide both sides by

a + b; ab \neq = 0, a \neq = - b

x = - \frac{3 ab}{a + b}; ab \neq = 0, a \neq = - b

10 x + 4 = 0

y, y = 2 e^{- 3 t}

- \frac{3}{10} + \frac{x}{2} = 0.5

v = \frac{4}{3} π (5)^{3}

8 - (3 x - 3) = x - (2 x - 1)

What is the answer to (x+2a)/a+(x+3b)/b =2 ?
The answer to (x+2a)/a+(x+3b)/b =2 is x=-(3ab)/(a+b);\quad ab\ne 0,a\ne-b