What is the answer to solvefor x,f^{-1}(x)=5x ?

The answer to solvefor x,f^{-1}(x)=5x is x=0;\quad f\ne 0

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solvefor x,f^{-1}(x)=5x

solve for

x, f^{- 1} (x) = 5 x

x = 0; f \neq = 0

Solution steps

f^{- 1} (x) = 5 x

Expand

f^{- 1} (x) : \frac{x}{f}

\frac{x}{f} = 5 x

Multiply both sides by

f

x = 5 x f; f \neq = 0

Move

5 x f

to the left side

x - 5 x f = 0; f \neq = 0

Factor

x - 5 x f : x (1 - 5 f)

x (1 - 5 f) = 0; f \neq = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0; f \neq = 0

\frac{2 ( z - 8 )}{12} = \frac{3}{2}

x^{2} + 81 = x^{2} + 100

x, 3 x - 3 y = - 9

a, a + 2 b = 10

\frac{x}{6400} = \frac{90}{360}

What is the answer to solvefor x,f^{-1}(x)=5x ?
The answer to solvefor x,f^{-1}(x)=5x is x=0;\quad f\ne 0