What is the answer to solvefor x,y^3-2xy+7=3x+1 ?

The answer to solvefor x,y^3-2xy+7=3x+1 is x=-(-y^3-6)/(3+2y);\quad y\ne-3/2

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solvefor x,y^3-2xy+7=3x+1

solve for

x, y^{3} - 2 x y + 7 = 3 x + 1

x = - \frac{- y ^{3} - 6}{3 + 2 y}; y \neq = - \frac{3}{2}

Solution steps

y^{3} - 2 x y + 7 = 3 x + 1

Move

y^{3}

to the right side

- 2 x y + 7 = 3 x + 1 - y^{3}

Move

7

to the right side

- 2 x y = 3 x - y^{3} - 6

Move

3 x

to the left side

- 2 x y - 3 x = - y^{3} - 6

Factor

- 2 x y - 3 x : - x (2 y + 3)

- x (2 y + 3) = - y^{3} - 6

Divide both sides by

- (2 y + 3); y \neq = - \frac{3}{2}

x = - \frac{- y ^{3} - 6}{3 + 2 y}; y \neq = - \frac{3}{2}

lo g_{10} (987) = a

\frac{2}{3} x + \frac{1}{2} (x - 3) = \frac{( x + 1 )}{4}

\frac{3 ( \frac{- 2 - ( - 6 )}{3} )}{8} (11 + 3 x + 5 x) = - 2.5

90 + 40 + x + 57 = 180

\frac{1}{3} + 3 \frac{1}{3} + 5 \frac{2}{3} = 13 \frac{5}{3}, A = 2

What is the answer to solvefor x,y^3-2xy+7=3x+1 ?
The answer to solvefor x,y^3-2xy+7=3x+1 is x=-(-y^3-6)/(3+2y);\quad y\ne-3/2