What is the answer to solvefor x,(x-2t)/a =(3(x-y))/z ?

The answer to solvefor x,(x-2t)/a =(3(x-y))/z is x=(-3ay+2tz)/(z-3a);\quad a\ne 0,z\ne 0,a\ne z/3

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solvefor x,(x-2t)/a =(3(x-y))/z

solve for

x, \frac{x - 2 t}{a} = \frac{3 ( x - y )}{z}

x = \frac{- 3 a y + 2 t z}{z - 3 a}; a \neq = 0, z \neq = 0, a \neq = \frac{z}{3}

Solution steps

\frac{x - 2 t}{a} = \frac{3 ( x - y )}{z}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(x - 2 t) z = a \cdot 3 (x - y)

Expand

(x - 2 t) z : x z - 2 t z

Expand

a \cdot 3 (x - y) : 3 a x - 3 a y

x z - 2 t z = 3 a x - 3 a y; a \neq = 0, z \neq = 0

Move

2 t z

to the right side

x z = 3 a x - 3 a y + 2 t z; a \neq = 0, z \neq = 0

Move

3 a x

to the left side

x z - 3 a x = - 3 a y + 2 t z; a \neq = 0, z \neq = 0

Factor

x z - 3 a x : x (z - 3 a)

x (z - 3 a) = - 3 a y + 2 t z; a \neq = 0, z \neq = 0

Divide both sides by

z - 3 a; a \neq = 0, z \neq = 0, a \neq = \frac{z}{3}

x = \frac{- 3 a y + 2 t z}{z - 3 a}; a \neq = 0, z \neq = 0, a \neq = \frac{z}{3}

\frac{4 x + 23}{5} = 3

- 2 w + 6 = 16

x, - \frac{x}{2} + \frac{y}{5} = 1

x, 3 x + 9 y = 54

x, 2 x + 2 y + 1 = 0

What is the answer to solvefor x,(x-2t)/a =(3(x-y))/z ?
The answer to solvefor x,(x-2t)/a =(3(x-y))/z is x=(-3ay+2tz)/(z-3a);\quad a\ne 0,z\ne 0,a\ne z/3