What is the answer to R=1+3(2^2+1)(2^4+1)(2^8+1) ?

The answer to R=1+3(2^2+1)(2^4+1)(2^8+1) is R=65536

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R=1+3(2^2+1)(2^4+1)(2^8+1)

R = 1 + 3 (2^{2} + 1) (2^{4} + 1) (2^{8} + 1)

R = 65536

Solution steps

R = 1 + 3 (2^{2} + 1) (2^{4} + 1) (2^{8} + 1)

Simplify

1 + 3 (2^{2} + 1) (2^{4} + 1) (2^{8} + 1) : 65536

R = 65536

\frac{1}{3} x + 7 = 15

4 (2 x - 3) = 2 - (6 - x)

5 (1 + x) = 5 x + 5

4 x + 6 + 2 x + 8 = 50

\frac{2 x - 1}{3} = x - \frac{x - 1}{5}

What is the answer to R=1+3(2^2+1)(2^4+1)(2^8+1) ?
The answer to R=1+3(2^2+1)(2^4+1)(2^8+1) is R=65536
Solve for R: R=1+3(2^2+1)(2^4+1)(2^8+1)
The solution is R=65536