What is the answer to (x-3)^2+5x=(x+2)^2 ?

The answer to (x-3)^2+5x=(x+2)^2 is x=1

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(x-3)^2+5x=(x+2)^2

(x - 3)^{2} + 5 x = (x + 2)^{2}

x = 1

Solution steps

(x - 3)^{2} + 5 x = (x + 2)^{2}

Expand

(x - 3)^{2} + 5 x : x^{2} - x + 9

Expand

(x + 2)^{2} : x^{2} + 4 x + 4

x^{2} - x + 9 = x^{2} + 4 x + 4

Move

9

to the right side

x^{2} - x = x^{2} + 4 x - 5

Subtract

x^{2} + 4 x

from both sides

x^{2} - x - (x^{2} + 4 x) = x^{2} + 4 x - 5 - (x^{2} + 4 x)

Simplify

- 5 x = - 5

Divide both sides by

- 5

x = 1

G, F = G \frac{mm}{r ^{2}}

\frac{x}{6} + \frac{1}{2} = \frac{4}{3}

\frac{3 x + 8}{3} = \frac{2 x - 1}{6}

x, x + y + z = 100

3 z + 35 = 47

What is the answer to (x-3)^2+5x=(x+2)^2 ?
The answer to (x-3)^2+5x=(x+2)^2 is x=1
Solve for x: (x-3)^2+5x=(x+2)^2
The solution is x=1