What are the solutions to the equation -x^2-3x+9=0 ?

The solutions to the equation -x^2-3x+9=0 are x=-(3+3sqrt(5))/2 ,x=(3sqrt(5)-3)/2

Find the zeros of -x^2-3x+9=0

The zeros of -x^2-3x+9=0 are x=-(3+3sqrt(5))/2 ,x=(3sqrt(5)-3)/2

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- x^{2} - 3 x + 9 = 0

x = - \frac{3 + 3 5}{2}, x = \frac{3 5 - 3}{2}

Decimal Notation

x = - 4.85410 \dots, x = 1.85410 \dots

Solution steps

- x^{2} - 3 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 9}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 9 = 35

x_{1, 2} = \frac{- ( - 3 ) \pm 3 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 3 5}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 3 5}{2 ( - 1 )} : - \frac{3 + 3 5}{2}

x = \frac{- ( - 3 ) - 3 5}{2 ( - 1 )} : \frac{3 5 - 3}{2}

The solutions to the quadratic equation are:

x = - \frac{3 + 3 5}{2}, x = \frac{3 5 - 3}{2}

\frac{- x}{3} = 2

\frac{1}{\frac{24}{25}}

72 x ab - 168 xv + 96 x a - 126 xv b

z^{2} - 3 z - 4

x + \frac{x}{2} = 78

What are the solutions to the equation -x^2-3x+9=0 ?
The solutions to the equation -x^2-3x+9=0 are x=-(3+3sqrt(5))/2 ,x=(3sqrt(5)-3)/2
Find the zeros of -x^2-3x+9=0
The zeros of -x^2-3x+9=0 are x=-(3+3sqrt(5))/2 ,x=(3sqrt(5)-3)/2