What is the answer to x(0)=0^3,y(0)=0^2,0<= 0<= 2 ?

The answer to x(0)=0^3,y(0)=0^2,0<= 0<= 2 is True for all x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x(0)=0^3,y(0)=0^2,0<= 0<= 2

x (0) = 0^{3}, y (0) = 0^{2}, 0 \leq 0 \leq 2

True for all x

Solution steps

x (0) = 0^{3}

Remove parentheses:

(a) = a

x \cdot 0 = 0^{3}

Apply rule

0 \cdot a = 0

0 = 0^{3}

Apply rule

0^{a} = 0

0 = 0

Both sides are equal

True for all x

- \frac{1}{4} + \frac{11}{12} x = - \frac{1}{4}

\frac{x}{3} + \frac{x}{4} = 14

x, - 4 x - 2 y = 12

x, b x + kb - 1 + \frac{x}{b} = 0

3 x + 7 = 16 + 2 x

What is the answer to x(0)=0^3,y(0)=0^2,0<= 0<= 2 ?
The answer to x(0)=0^3,y(0)=0^2,0<= 0<= 2 is True for all x