What is the answer to -3x-[-6x-(3-x)]=9+(x-1) ?

The answer to -3x-[-6x-(3-x)]=9+(x-1) is x=5

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-3x-[-6x-(3-x)]=9+(x-1)

- 3 x - [- 6 x - (3 - x)] = 9 + (x - 1)

x = 5

Solution steps

- 3 x - [- 6 x - (3 - x)] = 9 + (x - 1)

Remove parentheses:

(a) = a

- 3 x - [- 6 x - (3 - x)] = 9 + x - 1

Group like terms

- 3 x - [- 6 x - (3 - x)] = x + 9 - 1

Add/Subtract the numbers:

9 - 1 = 8

- 3 x - [- 6 x - (3 - x)] = x + 8

Expand

- 3 x - (- 6 x - (3 - x)) : 2 x + 3

2 x + 3 = x + 8

Move

3

to the right side

2 x = x + 5

Move

x

to the left side

x = 5

\frac{3 x - 2}{4} = \frac{2 x + 1}{5}

24 x - 4 = 0

72 f - 12 g = 96

(x) = 7 x + 150

x, x + 3 - (- 7) + 4 + (- 2) \cdot 6 = - y

What is the answer to -3x-[-6x-(3-x)]=9+(x-1) ?
The answer to -3x-[-6x-(3-x)]=9+(x-1) is x=5
Solve for x: -3x-[-6x-(3-x)]=9+(x-1)
The solution is x=5