What is the answer to 2x^2-(x+1)^2+3x=x(x-2)+5 ?

The answer to 2x^2-(x+1)^2+3x=x(x-2)+5 is x=2

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2x^2-(x+1)^2+3x=x(x-2)+5

2 x^{2} - (x + 1)^{2} + 3 x = x (x - 2) + 5

x = 2

Solution steps

2 x^{2} - (x + 1)^{2} + 3 x = x (x - 2) + 5

Expand

x (x - 2) : x^{2} - 2 x

x^{2} + x - 1 = x^{2} - 2 x + 5

Expand

2 x^{2} - (x + 1)^{2} + 3 x : x^{2} + x - 1

x^{2} + x - 1 = x^{2} - 2 x + 5

Move

1

to the right side

x^{2} + x = x^{2} - 2 x + 6

Subtract

x^{2} - 2 x

from both sides

x^{2} + x - (x^{2} - 2 x) = x^{2} - 2 x + 6 - (x^{2} - 2 x)

Simplify

3 x = 6

Divide both sides by

3

x = 2

\frac{2 x}{3} - 2 = \frac{x}{3} + 1

- 46 = 4 y - 5 (y + 7)

z = (3 - 3 i) - 12

\frac{2 x - 5}{3} - \frac{4 x - 1}{2} = \frac{5}{6}

x^{(2)} + 6 x + 9 = (x + 3)^{(2)}

What is the answer to 2x^2-(x+1)^2+3x=x(x-2)+5 ?
The answer to 2x^2-(x+1)^2+3x=x(x-2)+5 is x=2
Solve for x: 2x^2-(x+1)^2+3x=x(x-2)+5
The solution is x=2