What is the answer to D=(x-3)(x+3)-(x+2)(x-2)+5 ?

The answer to D=(x-3)(x+3)-(x+2)(x-2)+5 is True for all x;\quad-5=D-5

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D=(x-3)(x+3)-(x+2)(x-2)+5

D = (x - 3) (x + 3) - (x + 2) (x - 2) + 5

True for all x; - 5 = D - 5

Solution steps

D = (x - 3) (x + 3) - (x + 2) (x - 2) + 5

Switch sides

(x - 3) (x + 3) - (x + 2) (x - 2) + 5 = D

Move

5

to the right side

(x - 3) (x + 3) - (x + 2) (x - 2) = D - 5

Expand

(x - 3) (x + 3) - (x + 2) (x - 2) : - 5

- 5 = D - 5

Both sides are equal

True for all x; - 5 = D - 5

\frac{1.2}{291} = \frac{x}{358}

- 9 x + 3 (x + 1) + 8 = - x - 10

\frac{3 x + 2}{5} - 7 = 2 x - \frac{x + 1}{2}

y, x - 2 y + 3 z = 4

- 10 x + 9 = - 81

What is the answer to D=(x-3)(x+3)-(x+2)(x-2)+5 ?
The answer to D=(x-3)(x+3)-(x+2)(x-2)+5 is True for all x;\quad-5=D-5