What is the answer to 3(2+v)-v=4+2(v+1) ?

The answer to 3(2+v)-v=4+2(v+1) is True for all v

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3(2+v)-v=4+2(v+1)

3 (2 + v) - v = 4 + 2 (v + 1)

True for all v

Solution steps

3 (2 + v) - v = 4 + 2 (v + 1)

Expand

3 (2 + v) : 6 + 3 v

6 + 3 v - v = 4 + 2 (v + 1)

Add similar elements:

3 v - v = 2 v

6 + 2 v = 4 + 2 (v + 1)

Expand

4 + 2 (v + 1) : 2 v + 6

6 + 2 v = 2 v + 6

Move

6

to the right side

2 v = 2 v

Move

2 v

to the left side

0 = 0

Both sides are equal

True for all v

2 t \geq 10

e^{2 πi}

a^{2} - 2 a d + d^{2}

\frac{3}{8 p ^{2} q} + \frac{5}{4 p ^{2} q}

x + \frac{4}{9} = \frac{3}{4}

What is the answer to 3(2+v)-v=4+2(v+1) ?
The answer to 3(2+v)-v=4+2(v+1) is True for all v
Solve for v: 3(2+v)-v=4+2(v+1)
The solution is True for all v