What is the answer to solvefor x,xy=3x+2y+z ?

The answer to solvefor x,xy=3x+2y+z is x=(2y+z)/(y-3);\quad y\ne 3

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solvefor x,xy=3x+2y+z

solve for

x, x y = 3 x + 2 y + z

x = \frac{2 y + z}{y - 3}; y \neq = 3

Solution steps

x y = 3 x + 2 y + z

Move

3 x

to the left side

x y - 3 x = 2 y + z

Factor

x y - 3 x : x (y - 3)

x (y - 3) = 2 y + z

Divide both sides by

y - 3; y \neq = 3

x = \frac{2 y + z}{y - 3}; y \neq = 3

2.5 f - 5 = 1.5 f + 10

h, h (\frac{3}{5})^{2} + k (\frac{3}{5}) - 12 = 0

3 (4 x + 1) = - 3 (3 x - 2) + 4 x

\frac{4 x - 2}{8} - \frac{5 x - 3}{4} = \frac{2 x - 1}{6}

x + 4 = 3 x - 10

What is the answer to solvefor x,xy=3x+2y+z ?
The answer to solvefor x,xy=3x+2y+z is x=(2y+z)/(y-3);\quad y\ne 3