What is the answer to (3x)/2-(2x)/3-2=1-1/3 ?

The answer to (3x)/2-(2x)/3-2=1-1/3 is x= 16/5

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(3x)/2-(2x)/3-2=1-1/3

\frac{3 x}{2} - \frac{2 x}{3} - 2 = 1 - \frac{1}{3}

x = \frac{16}{5}

Decimal Notation

x = 3.2

Solution steps

\frac{3 x}{2} - \frac{2 x}{3} - 2 = 1 - \frac{1}{3}

Simplify

1 - \frac{1}{3} : \frac{2}{3}

\frac{3 x}{2} - \frac{2 x}{3} - 2 = \frac{2}{3}

Multiply by LCM

5 x - 12 = 4

Move

12

to the right side

5 x = 16

Divide both sides by

5

x = \frac{16}{5}

4 + m = 24

2 (8 z + 20) = - 19

\frac{( 2 x - 1 )}{3} + \frac{( 3 x + 4 )}{4} = \frac{7 ( x + 3 )}{10}

3 x - 5 = 2 x + 2

8 x - (x - 4) = 2 (x - 8)

What is the answer to (3x)/2-(2x)/3-2=1-1/3 ?
The answer to (3x)/2-(2x)/3-2=1-1/3 is x= 16/5
Solve for x: (3x)/2-(2x)/3-2=1-1/3
The solution is x= 16/5