What are the solutions to the equation 4x^2+32x+7=0 ?

The solutions to the equation 4x^2+32x+7=0 are x=(-8+sqrt(57))/2 ,x=-(8+sqrt(57))/2

Find the zeros of 4x^2+32x+7=0

The zeros of 4x^2+32x+7=0 are x=(-8+sqrt(57))/2 ,x=-(8+sqrt(57))/2

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4 x^{2} + 32 x + 7 = 0

x = \frac{- 8 + 57}{2}, x = - \frac{8 + 57}{2}

Decimal Notation

x = - 0.22508 \dots, x = - 7.77491 \dots

Solution steps

4 x^{2} + 32 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

3 2^{2} - 4 \cdot 4 \cdot 7 = 457

x_{1, 2} = \frac{- 32 \pm 4 57}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 32 + 4 57}{2 \cdot 4}, x_{2} = \frac{- 32 - 4 57}{2 \cdot 4}

x = \frac{- 32 + 4 57}{2 \cdot 4} : \frac{- 8 + 57}{2}

x = \frac{- 32 - 4 57}{2 \cdot 4} : - \frac{8 + 57}{2}

The solutions to the quadratic equation are:

x = \frac{- 8 + 57}{2}, x = - \frac{8 + 57}{2}

(\frac{1}{x})^{- 2}

6 4^{3} + 1

- 10 x^{2} + 70 x

(\frac{x ^{4}}{x ^{- 3} y ^{- 4}})^{- 2}

X^{2} + X + 1 = 0

What are the solutions to the equation 4x^2+32x+7=0 ?
The solutions to the equation 4x^2+32x+7=0 are x=(-8+sqrt(57))/2 ,x=-(8+sqrt(57))/2
Find the zeros of 4x^2+32x+7=0
The zeros of 4x^2+32x+7=0 are x=(-8+sqrt(57))/2 ,x=-(8+sqrt(57))/2