What is the answer to (x-7)(x-3/4)-x^2=0 ?

The answer to (x-7)(x-3/4)-x^2=0 is x= 21/31

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(x-7)(x-3/4)-x^2=0

(x - 7) (x - \frac{3}{4}) - x^{2} = 0

x = \frac{21}{31}

Decimal Notation

x = 0.67741 \dots

Solution steps

(x - 7) (x - \frac{3}{4}) - x^{2} = 0

Expand

(x - 7) (x - \frac{3}{4}) - x^{2} : - \frac{31}{4} x + \frac{21}{4}

- \frac{31}{4} x + \frac{21}{4} = 0

Multiply both sides by

4

- 31 x + 21 = 0

Move

21

to the right side

- 31 x = - 21

Divide both sides by

- 31

x = \frac{21}{31}

\frac{1}{2} (\frac{3 x}{4} + \frac{5}{3}) = - (\frac{1}{4} + x)

2 y + 3 = 4 y + 2

x + 10 = 2 (x + 4)

10 + 6 x = 8 + 14 x - 8 x

\frac{1}{4} b + \frac{2}{5} b - 5 = - 3

What is the answer to (x-7)(x-3/4)-x^2=0 ?
The answer to (x-7)(x-3/4)-x^2=0 is x= 21/31
Solve for x: (x-7)(x-3/4)-x^2=0
The solution is x= 21/31